90n+23p=4523.If n and p are positive integers in the equatio
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90n+23p=4523.If n and p are positive integers in the equation above,what is one possible value of n+p?
怎么算?
是51,118和185
怎么算?
是51,118和185
n、p 均为正整数
90n+23p=4523
n=4523/90 - 23/90 p
n+p=4523/90 - 23/90 p +p=(4523+67p)/90 属于正整数
所以4523+67p)是90的倍数
所以当p=1时就符合
n+p=(4523+67)/90=51
由于电脑上不便于操作没有用数学符号,你自己写答案的时候一定要记得用数学符号哟!
90n+23p=4523
n=4523/90 - 23/90 p
n+p=4523/90 - 23/90 p +p=(4523+67p)/90 属于正整数
所以4523+67p)是90的倍数
所以当p=1时就符合
n+p=(4523+67)/90=51
由于电脑上不便于操作没有用数学符号,你自己写答案的时候一定要记得用数学符号哟!
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