int a[]={1,2,3,4,5,6,7,8,9},*p; for(p=a,p
int a[]={1,2,3,4,5,6,7,8,9},*p; for(p=a,p
int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int **p; p=(int**)a;
{ int a[]={1,2,3,4,5,6}; int*p; p=a; printf("%d\n",*p); prin
C语言 int a[ ]={0,1,2,3,4,5,6,7,8,9},*p=a *p=a 是不是相当于 *(p=a)
#include main(){int a[]={1,2,3,4,5,6,7,8,9,0},*p; p=a; print
int[][4]={1,2,3,4,5,6,7,8};int(*p)[4]=a;则表达式**(p+1)-*(*p+1)的
有如下程序,int a[10]={1,2,3,4,5,6,7,8,9,10}; int *p=&a[3],b;b=p[5
int a[5]={2,4,6,8,10},*P,* *k; p=a; k=&p; printf("%d",*(p++)
设有说明”static int a [3][3]={{1},{4,5},{7,8,9}},*p=a[2];”,则*(p-
int *p,a[10]; for(p=a;p
int a[3][5]={{1,2},{6,4},{3,4,5}}; int (*p)[5] = a; 求*(*p+1)
main(){int a[]={2,4,6,8,10};int y=1,x,*p;p=&a[1];for(x=0;x