八上数学分式题:先化简再求值a-b分之a+b-a+b分之a-b-a²-b²分之3ab,其中a=3,b
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八上数学分式题:先化简再求值a-b分之a+b-a+b分之a-b-a²-b²分之3ab,其中a=3,b=-2
计算x²-1分之a+b+x+1分之b=
x-1分之2-2-2x分之1-3x=
已知x²+xy+y²=0,则x分之y+y分之x=
计算x²-y²分之x+y+y²-x²分之2y
a²-2a+1分之a²-1+a²-1分之a-a²
计算x²-1分之a+b+x+1分之b=
x-1分之2-2-2x分之1-3x=
已知x²+xy+y²=0,则x分之y+y分之x=
计算x²-y²分之x+y+y²-x²分之2y
a²-2a+1分之a²-1+a²-1分之a-a²
![八上数学分式题:先化简再求值a-b分之a+b-a+b分之a-b-a²-b²分之3ab,其中a=3,b](/uploads/image/z/3954955-67-5.jpg?t=%E5%85%AB%E4%B8%8A%E6%95%B0%E5%AD%A6%E5%88%86%E5%BC%8F%E9%A2%98%EF%BC%9A%E5%85%88%E5%8C%96%E7%AE%80%E5%86%8D%E6%B1%82%E5%80%BCa-b%E5%88%86%E4%B9%8Ba%2Bb-a%2Bb%E5%88%86%E4%B9%8Ba-b-a%26%23178%3B-b%26%23178%3B%E5%88%86%E4%B9%8B3ab%2C%E5%85%B6%E4%B8%ADa%3D3%2Cb)
(a+b)/(a-b) -(a-b)/(a+b) -3ab/(a^2-b^2)
=(a+b)^2/[(a-b)*(a+b)] -(a-b)^2/[(a+b)*(a-b) ] -3ab/(a^2-b^2)
=[(a+b)^2-(a-b)^2-3ab]/(a^2-b^2)
=ab/(a^2-b^2)
=3*(-2)/[3^2 -(-2)^2]
=-6/(9-4)
=-6/5
(a+b)/(x^2-1) + b/(x+1)
=(a+b)/[(x+1)(x-1)]+b(x-1)/[(x+1)(x-1)]
=(a+b+bx-b)/(x^2-1)
=(a+bx)/(x^2-1)
2/(x-1) -(1-3x)/(2-2x)
=2/(x-1)-(3x-1)/2(x-1)
=4/2(x-1)-(3x-1)/2(x-1)
=(4-3x+1)/2(x-1)
=-3(x-1)/2(x-1)
=-3/2
x^2+xy+y^2=0 两边同时除以xy
x/y+1+y/x=0
x/y +y/x=-1
(x+y)/(x^2-y^2) +2y/(y^2-x^2)
=(x+y)/(x^2-y^2) -2y/(x^2-y^2)
=(x+y-2y)/(x^2-y^2)
=(x-y)/[(x-y)(x+y)]
=1/(x+y)
(a^2-1)/(a^2-2a+1) +(a-a^2)/(a^2-1)
=(a-1)(a+1)/(a-1)^2 +(a-a^2)/(a^2-1)
=(a+1)/(a-1) + (a-a^2)/(a-1)(a+1)
=(a+1)^2/[(a-1)(a+1)] +(a-a^2)/(a-1)(a+1)
=[(a+1)^2 +(a-a^2)]/[(a-1)(a+1)]
=(3a+1)/(a^2-1)
=(a+b)^2/[(a-b)*(a+b)] -(a-b)^2/[(a+b)*(a-b) ] -3ab/(a^2-b^2)
=[(a+b)^2-(a-b)^2-3ab]/(a^2-b^2)
=ab/(a^2-b^2)
=3*(-2)/[3^2 -(-2)^2]
=-6/(9-4)
=-6/5
(a+b)/(x^2-1) + b/(x+1)
=(a+b)/[(x+1)(x-1)]+b(x-1)/[(x+1)(x-1)]
=(a+b+bx-b)/(x^2-1)
=(a+bx)/(x^2-1)
2/(x-1) -(1-3x)/(2-2x)
=2/(x-1)-(3x-1)/2(x-1)
=4/2(x-1)-(3x-1)/2(x-1)
=(4-3x+1)/2(x-1)
=-3(x-1)/2(x-1)
=-3/2
x^2+xy+y^2=0 两边同时除以xy
x/y+1+y/x=0
x/y +y/x=-1
(x+y)/(x^2-y^2) +2y/(y^2-x^2)
=(x+y)/(x^2-y^2) -2y/(x^2-y^2)
=(x+y-2y)/(x^2-y^2)
=(x-y)/[(x-y)(x+y)]
=1/(x+y)
(a^2-1)/(a^2-2a+1) +(a-a^2)/(a^2-1)
=(a-1)(a+1)/(a-1)^2 +(a-a^2)/(a^2-1)
=(a+1)/(a-1) + (a-a^2)/(a-1)(a+1)
=(a+1)^2/[(a-1)(a+1)] +(a-a^2)/(a-1)(a+1)
=[(a+1)^2 +(a-a^2)]/[(a-1)(a+1)]
=(3a+1)/(a^2-1)
八上数学分式题:先化简再求值a-b分之a+b-a+b分之a-b-a²-b²分之3ab,其中a=3,b
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