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延长四边形ABCD的对边AD,BC交于F;DC,AB交于E,若角AED,角AFB平分线交于O,求证:角EOF=1/2(角

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延长四边形ABCD的对边AD,BC交于F;DC,AB交于E,若角AED,角AFB平分线交于O,求证:角EOF=1/2(角EAF+角BCD)
延长四边形ABCD的对边AD,BC交于F;DC,AB交于E,若角AED,角AFB平分线交于O,求证:角EOF=1/2(角
证明:连接OA
      ∵角AED,角AFB平分线交于O
      ∴ ∠EOF=∠OAB+1/2∠F+∠OAD+1/2∠E
              =∠EAF+1/2∠F+1/2∠E   ①
     又 ∠BCD=∠F+∠CDF
             =∠F+∠EAF+∠E ②
    由①②得 ∠EOF=∠EAF+1/2∠F+1/2∠E
                  =1/2∠EAF+1/2∠EAF+1/2∠F+1/2∠E
                  =1/2∠EAF+1/2∠BCD
                  =1/2(∠EAF+∠BCD)
   ∴角EOF=1/2(角EAF+角BCD)