在Rt△ABC中,∠bac=90°,ab=ac,ad=dc,ae⊥bd,求证∠ADB=∠CDE
在Rt△ABC中,∠bac=90°,ab=ac,ad=dc,ae⊥bd,求证∠ADB=∠CDE
如图,已知在Rt 三角形ABC中,∠BAC=90°,AB=AC,AD=DC,AE⊥BD于N,求证∠ADB=∠CDE
在RT三角形ABC中,角BAC=90度,AB=AC,AD=DC,AE垂直BD于N.求证:角ADB=角CDE.
如图,在直角三角形ABC中,角BAC=90度,AB=AC,AD=DC,AE垂直BD于M,求证:角ADB=角CDE
几何,聪明的人来如图,∠BAC=90 AB=AC AD=DC AE⊥BD 求证:∠ADB=∠CDE好的追加分数
第一题:如图,已知∠BAC=90°,AB=BC,AD=DC,AE⊥BD.求证∠ADB=∠CDE(写出四种证法)
已知∠BAC=90°,AD=DC,AB=AC,AE⊥BD.证明∠ADB=∠CDE.
如图,在直角三角形ABC中,∠BAC=90º,AB=AC,AD=DC,AE⊥BD,垂足为N 求证:∠ADB=∠
已知△ABC中,AB=AC,角BAC=90°,AD=DC,AE⊥BD交BC于E试说明角ADB=角CDE
RT△ABC中,AB=AC,AE=BF,BD=DC,∠BAC=90,求证:DE=DF且DE⊥DF
如图,在△ABC中,∠BAC=90°,AB=AC,点D为AC中点,AE⊥BD于点E,AE交BC于点F,求证:∠ADB=∠
已知在△ABC中,∠BAC=90°,AB=AC,D为AC的中点,AE⊥BD于E,延长AE交BC于F,求证:∠ADB=∠C