6(x-10)=y-10
若(x-2)*2+15y-11=0,求-3(2x-y)-{7x-〔6x+2y-(10x-8y)〕
已知4x²+y²-4x-6y+10=0求(2/3x(√9x)+(y²√x/y³)
y=根号(x²-2x+10)+根号(x²-6x+13) 求y值域 X定义域
6(x-10)=y-10
设实数x,y满足方程:x^+y^-8x-6y+21=0,求:(1)2x-y的取值范围 (2)x^+y^-10x+2y+2
解方程组 2x+y=(4x-y-1)/2=(10+6x+2y)/4
2x+y=(4x-y-1)/2=(10+6x+2y)/4
x+y=6 10x+y≤42
1.已知,x+y=-6,x-y=5 A.(x+y)²=-36 B.(y-x)²=-10 C.xy=2
用加减法解方程组:{(x+y)/6+(x-y)/10=3 (x+y)/6+(y-x)/10=-1
解方程组x+y/6+x-y/10=3,x+y/6+y-x/10=-1
(1)x+y=7 (2)3x+2y=-10 2x-5y=-21 2x+y=-6