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已知X平方+4X-1=0,那么2X4次方-4X平方-8X+1的值

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已知X平方+4X-1=0,那么2X4次方-4X平方-8X+1的值
X平方怎么写?
已知X平方+4X-1=0,那么2X4次方-4X平方-8X+1的值
x^2 + 4x - 1 = 0
求 2x^4 - 4x^2 - 8x + 1 =
2x^4 - 4x^2 - 8x + 1
= 2x^2(x^2 + 4x - 1) - 8x^3 + 2x^2 - 4x^2 - 8x + 1
= - 8x^3 + 2x^2 - 4x^2 - 8x + 1
= -8x(x^2 + 4x - 1) + 32x^2 - 8x - 2x^2 - 8x + 1
= 32x^2 - 8x - 2x^2 - 8x + 1
= 30x^2 - 16x + 1
= 30(x^2 + 4x - 1) - 120x + 30 - 16x + 1
= - 120x + 30 - 16x + 1
= - 136x + 31
x^2 + 4x - 1 = 0
x =[ -4 +- (16 + 4)^(1/2) ]/ 2
= -2 +- 5^(1/2)
2x^4 - 4x^2 - 8x + 1
= 31 - 136 * (-2 +- 5^(1/2))
= 303 +- 136 * 5^(1/2)