已知tanx=根号下7,求(1--cos2x+sin2x)/(1+cos2x+sin2x)的值(请写过程)

来源：学生作业帮编辑：搜搜考试网作业帮分类：数学作业时间：2024/04/29 19:21:19

(1--cos2x+sin2x)/(1+cos2x+sin2x)=(1-(1-2sin^x)+2sinxcosx)/(1+(2cos^x-1)+2sinxcosx)=(2sin^x+2sinxcosx)/(2cos^x+2sinxcosx)=(sinx/cosx)[(sinx+cosx)/(cosx+sinx)]=sinx/cosx=tanx=根号7

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