f(n)=1/(n+1) + 1/(n+2) + 1/(n+3) + …… + 1/(2n),(n∈整数,且n≥2),求
f(n)=1/(n+1) + 1/(n+2) + 1/(n+3) + …… + 1/(2n),(n∈整数,且n≥2),求
证明不等式:(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
f(n)=1/(n+1)+1/(n+2)+1/(n+3)……+1/2n (n∈N*),f(n+1
f(n)=1/(n+1)+1/(n+2)+…+1/(2n-1)+1/(2n) (n≥2,n∈N*)
求极限Xn=n/(n^2+1)+n/(n^2+2)+n/(n^2+3)+……+n/(n^2+n),
2^n/n*(n+1)
(1/(n^2 n 1 ) 2/(n^2 n 2) 3/(n^2 n 3) ……n/(n^2 n n)) 当N越于无穷大
1、若f(n)=[n²+1]-n,g(n)=n-[n²-1],h(n)=1/(2n),求f(n),g
如果,n是大于2的整数,计算1/(n-1)(n-2)+1/(n-2)(n-3)+1/(n-3)(n-4)+……+1/(n
求极限 lim n[1/(n^2+1)+1/(n^2+2^2)+……+1/(n^n+n^n)] (n趋向于无穷大,n^n
用数学归纳法证明:1×2×3+2×3×4+…+n×(n+1)×(n+2)=n(n+1)(n+2)(n+3)4(n∈N
已知Sn=2+5n+8n^2+…+(3n-1)n^n-1(n∈N*)求Sn