球一到数学题：分解因式：x^4+y^4+z^4-2x²y²-2x²z²+2y&s

来源：学生作业帮编辑：搜搜考试网作业帮分类：数学作业时间：2024/06/06 03:17:36

球一到数学题：分解因式：x^4+y^4+z^4-2x²y²-2x²z²+2y²z²

x^4+y^4+z^4-2x^2y^2-2y^2z^2-2z^2x^2
=(x^4-2x^2y^2+y^4)+z^4-2y^2z^2+2z^2x^2-4z^2x^2
=(x^2-y^2)^2+2z^2(x^2-y^2)+z^4-4z^2x^2
=(x^2-y^2+z^2)^2-4z^2x^2
=(x^2-y^2+z^2+2zx)(x^2-y^2+z^2-2zx)
=[(x+z)^2-y^2][(x-z)^2-y^2]
=(x+y+z)(x-y+z)(x+y-z)(x-y-z)

球一到数学题：分解因式：x^4+y^4+z^4-2x²y²-2x²z²+2y&s 分解因式 x²（x²-y²）＋z²（y²-x²）（a+b) 已知多项式A=x²+2y²-z²,B=-4x²+3y²+2z² 已知x²+y²+z²-2x+4y-6z+14=0,求代数式（x-y-z）²&or 已知-3y=x+2z,求x²-9y²+4z²+4xz的值已知2X+3Y+4Z=10,求X²+3Y²+Z²的最小值已知多项式A=x²+2y+z²,B=-4x²+3y²+2z²,且A+B 分解因式：4x²+2xy-2y²+4x+7y-3= 把（2z²-2x²-2y²)²-16x²y²因式分解分解因式运用公式法4-12（x-y)+9(x-y)²(x²-2x)²+2(x² 几道分解因式的题,2X²-4X= 8m²n+2mn=a²x²y-axy² 已知实数X,Y,Z满足 X²-6XY+10Y²+4Y+∣Z²-3Z+2∣+4=0,求（X+