已知α=π/24,求sinα(sec4αsec3α+sec3αsec2α+sec2αsecα+secα)=?
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已知α=π/24,求sinα(sec4αsec3α+sec3αsec2α+sec2αsecα+secα)=?
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求具体化简过程
![已知α=π/24,求sinα(sec4αsec3α+sec3αsec2α+sec2αsecα+secα)=?](/uploads/image/z/7751555-35-5.jpg?t=%E5%B7%B2%E7%9F%A5%CE%B1%3D%CF%80%2F24%2C%E6%B1%82sin%CE%B1%28sec4%CE%B1sec3%CE%B1%2Bsec3%CE%B1sec2%CE%B1%2Bsec2%CE%B1sec%CE%B1%2Bsec%CE%B1%29%3D%3F)
tan[(k+1)a]-tan(ka)
=sin[(k+1)a]/cos[(k+1)a]-sin(ka)/cos(ka)
=[cosasin[(k+1)a]-sinacos[(k+1)a]]/(cos[(k+1)a]cos(ka))
=sin([(k+1)a]-(ka))/(cos[(k+1)a]cos(ka))
=sina/cos[(k+1)a]cos(ka)
sinα(sec4αsec3α+sec3αsec2α+sec2αsecα+secα)=tan4α=(√3)/3
=sin[(k+1)a]/cos[(k+1)a]-sin(ka)/cos(ka)
=[cosasin[(k+1)a]-sinacos[(k+1)a]]/(cos[(k+1)a]cos(ka))
=sin([(k+1)a]-(ka))/(cos[(k+1)a]cos(ka))
=sina/cos[(k+1)a]cos(ka)
sinα(sec4αsec3α+sec3αsec2α+sec2αsecα+secα)=tan4α=(√3)/3
已知α=π/24,求sinα(sec4αsec3α+sec3αsec2α+sec2αsecα+secα)=?
sec3 x 的积分怎么求?老师要求把sec3 x 拆成sec x 和sec2 x.(3是3次方)求完整步骤.
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