java错误i cannot be resolved
来源:学生作业帮 编辑:搜搜考试网作业帮 分类:综合作业 时间:2024/06/08 08:21:46
java错误i cannot be resolved
求解这段代码出错:
int sum = 0;
for(int i = 0; i < 10; ++i)
{
if(i == 5)
break;
if(i > 3)
continue;
sum += i;
}
System.out.println(i+sum);//这里显示i cannot be resolved 错误
看懂了.
求解这段代码出错:
int sum = 0;
for(int i = 0; i < 10; ++i)
{
if(i == 5)
break;
if(i > 3)
continue;
sum += i;
}
System.out.println(i+sum);//这里显示i cannot be resolved 错误
看懂了.
System.out.println(i+sum);这里的i是不能使用的,因为这个i是循环里定义的私有变量
如果想实现你的需求,你就要将i定义在外面如:
int sum=0;
int i=0;
如果想实现你的需求,你就要将i定义在外面如:
int sum=0;
int i=0;
java错误i cannot be resolved
JAVA中报错i cannot be resolved to a variable
R.id cannot be resolved
cannot be resolved什么意识
ActionListenter cannot be resolved to a type
javax.servlet.jsp.JspException cannot be resolved to a type
The type javax.servlet.ServletContext cannot be resolved.It
java.lang.ClassCastException: java.lang.String cannot be cas
导入做好的java项目出现下面的错误The project cannot be built until build pa
在android中遇到了这种错误怎么解决The type java.lang.Object cannot be reso
java.lang.ClassCastException:pub.web.UserInfo cannot be cast
java.lang.ClassCastException:cn.itcast.domain.Role cannot be