如何用matlab解方程,在解出的实根和虚根中,求出实根?
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如何用matlab解方程,在解出的实根和虚根中,求出实根?
本人没用过matlab,
本人没用过matlab,
![如何用matlab解方程,在解出的实根和虚根中,求出实根?](/uploads/image/z/6364983-39-3.jpg?t=%E5%A6%82%E4%BD%95%E7%94%A8matlab%E8%A7%A3%E6%96%B9%E7%A8%8B%2C%E5%9C%A8%E8%A7%A3%E5%87%BA%E7%9A%84%E5%AE%9E%E6%A0%B9%E5%92%8C%E8%99%9A%E6%A0%B9%E4%B8%AD%2C%E6%B1%82%E5%87%BA%E5%AE%9E%E6%A0%B9%3F)
x=solve('x^3-x^2-x-2=0')
for k=1:length(x)
xx(k) = isreal(x(k));
end
X_real=x(xx)
y=solve('y^3-4*y^2+5*y-2')
for k=1:length(y)
yy(k) = isreal(y(k));
end
Y_real=y(yy)
运行结果:
x =
[ 2]
[ -1/2+1/2*i*3^(1/2)]
[ -1/2-1/2*i*3^(1/2)]
X_real =
2
y =
[ 2]
[ 1]
[ 1]
Y_real =
[ 2]
[ 1]
[ 1]
for k=1:length(x)
xx(k) = isreal(x(k));
end
X_real=x(xx)
y=solve('y^3-4*y^2+5*y-2')
for k=1:length(y)
yy(k) = isreal(y(k));
end
Y_real=y(yy)
运行结果:
x =
[ 2]
[ -1/2+1/2*i*3^(1/2)]
[ -1/2-1/2*i*3^(1/2)]
X_real =
2
y =
[ 2]
[ 1]
[ 1]
Y_real =
[ 2]
[ 1]
[ 1]