log2[log3(log4x)]=log3[log4(log2y)]=0求x+y的值,

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log2[log3(log4x)]=0=log2(1)
log3(log4x)=1=log3(3)
log4x=3=3log4(4)=log4(4^3)
x=4^3=64
log3[log4(log2y)]=0=log3(1)
log4(log2y)=1=log4(4)
log2y=4=4log2(2)=log2(2^4)
y=2^4=16
x+y=80
再问：因为我是今天刚刚学的这部分，老师布置的题中有这一个，说实话我一步也没看懂
再答：若loga(b)=loga(c)则b=c
loga(a)=1
loga(1)=0

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