请问tan(x/2)=sinx/(1+cosx)=(1-cosx)/sinx这是怎得到的?
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请问tan(x/2)=sinx/(1+cosx)=(1-cosx)/sinx这是怎得到的?
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![请问tan(x/2)=sinx/(1+cosx)=(1-cosx)/sinx这是怎得到的?](/uploads/image/z/6239198-38-8.jpg?t=%E8%AF%B7%E9%97%AEtan%28x%2F2%29%3Dsinx%2F%281%2Bcosx%29%3D%281-cosx%29%2Fsinx%E8%BF%99%E6%98%AF%E6%80%8E%E5%BE%97%E5%88%B0%E7%9A%84%3F)
tanx=(2tan(x/2))/(1-(tan(x/2))2)
1=(tan(x/2))2+(2tan(x/2))/tanx
(tan(x/2)+1/tanx)2=1+1/(tanx)2
因为1+1/(tanx)2=((tanx)2+1)/(tanx)2=1/(sinx)2
所以tan(x/2)+1/tanx=1/sinx
tan(x/2)=1/sinx-cosx/sinx=(1-cosx)/sinx
(sinx)2=(1+cosx)*(1-cosx) 1-cosx=(sinx)2/(1+cosx)
sinx/(1+cosx)=(1-cosx)/sinx
tan(x/2)=sinx/(1+cosx)=(1-cosx)/sinx (紧跟括号后面的是平方.)
1=(tan(x/2))2+(2tan(x/2))/tanx
(tan(x/2)+1/tanx)2=1+1/(tanx)2
因为1+1/(tanx)2=((tanx)2+1)/(tanx)2=1/(sinx)2
所以tan(x/2)+1/tanx=1/sinx
tan(x/2)=1/sinx-cosx/sinx=(1-cosx)/sinx
(sinx)2=(1+cosx)*(1-cosx) 1-cosx=(sinx)2/(1+cosx)
sinx/(1+cosx)=(1-cosx)/sinx
tan(x/2)=sinx/(1+cosx)=(1-cosx)/sinx (紧跟括号后面的是平方.)
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