计算:[23x−2x+y(x+y3x−x−y)]÷x−yx
计算:[23x−2x+y(x+y3x−x−y)]÷x−yx
化简求值:[23x−2x+y(x+y3x−x−y)]÷x−yx
当x−yx+y
若|x-y+3|与|x+y-1999|互为相反数,求x+2yx−y
解方程组2x−5=y3x−2y=12
若|x-y+3|与|x+y-1999|互为相反数,求x+yx−y
已知x=2009,y=2010,求式子x−yx÷(x−2xy−y
已知3x-5y=0,则分式x−2yx+3y
若丨x-y+3丨与丨x+y-1995丨互为相反数,则x+2yx−y
己知A=x−yx+y
已知:a=x−yx+y+3
设2x−yx+y=3,其中x,y≠0,则(2x−3y)3−(3x−2y)3(4x+2y)3−(x−7y)3=( )