若lim(2n-√4n^2+an+3)=1,n→∞,求a.
若lim(2n-√4n^2+an+3)=1,n→∞,求a.
lim (n→∞) (n^2/(an+b)-n^3/(2n^2-1))=1/4 求a,b
已知:lim (n→∞) [(n^2+n)/(n+1)-an-b]=1 ,求a,b的值
lim (n→∞) [(an^2+bn+c)/(2n+5)]=3,求a,b
等差数列{an},{bn}的前n项和分别为An,Bn,切An/Bn=2n/3n+1,求lim(n→∞)an/bn
已知数列an的前n项和Sn=(n^2+n)*3^n (1)求lim(n→∞)an/Sn (2).
求lim n→∞ (1+2/n)^n+3
若lim[(2n-1)an]=1 求lim(n*an)的值
证明两个简单极限1、lim n→∞ n/[(n!)^(1/n)]=e2、an→A 求证:lim n→∞ (a1+2a2+
求极限 lim(n→∞)[根号(n^2+4n+5)-(n-1)] =
求极限lim [ 2^(n+1)+3^(n+1)]/2^n+3^n (n→∞)
lim n →∞ (1^n+3^n+2^n)^1/n,求数列极限