希望杯的一个问题if the ratio of the degree of exterior angle of∠A,∠B

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希望杯的一个问题
if the ratio of the degree of exterior angle of∠A,∠B and ∠C.that are in the triangle ABC is 5:4:3,then the ratio of the degree of ∠A,∠B and ∠C is( ).
（A）5:4:3 （B）3:4:5 （C）1:2:3 （D）3:2:1
当x≠-5/b时，(a+x)/(-bx-5)成立，则a^2-b^2=( ).
（A）0 （B）1 （C）99.25 （D）99.75
If a-b+c＞0,then ( ).
(A)b(a+c)＞b^2 (B)(a+c)^2＞b（a+c) (C)1/(a+c)＜1/b (D)(a+c)^5＞b^5

我十分对不起,我英语的看不懂,但中文的还能解答.
当x≠-5/b时,(a+x)/(-bx-5)成立,则a^2-b^2=( D ).
（A）0 （B）1 （C）99.25 （D）99.75
答案为：D

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