数学题目:lim(n趋向无穷大) ((n+1)*(n+2)*(n+3))/(3*n*n) =1/3的计算过程 急需,谢谢
数学题目:lim(n趋向无穷大) ((n+1)*(n+2)*(n+3))/(3*n*n) =1/3的计算过程 急需,谢谢
极限计算 lim (1+2+3+...+n)/n^2=?(n趋向于无穷大)
lim n趋向无穷大(3^n+2^n)/(3^(n+1)-2^(n+1))=?
lim[(n+3)/(n+1))]^(n-2) 【n无穷大】
lim(n趋向无穷大)(根号下(n+3)-根号下n)*根号下(n-1)=
用极限的两边夹逼定理证明lim(1+2的n次方+3的n次方)的n次方分之一=3(n趋向无穷大)
求极限 lim n[1/(n^2+1)+1/(n^2+2^2)+……+1/(n^n+n^n)] (n趋向于无穷大,n^n
求数列的极限,lim(n趋向无穷大)(3n+5)/根号下n平方+n+4=?
紧急:求 lim n*sin(π(n^2+2)^0.5)*(-1)^n,n趋向无穷大;
证明lim(n/(n^2+1))=0(n趋向于无穷大)
lim(n趋向无穷大) 2^n/n!如何算
lim n->无穷大(2^n-1)/(3^n+1)