来源：学生作业帮 编辑：搜搜考试网作业帮 分类：数学作业 时间：2024/05/28 08:22:33
求做一道极限题
(tanx-sinx)/(sin^3*x) = (sinx/cosx-sinx)/(sin^3*x) and (sinx/cosx-sinx)/(sin^3*x) = (1-cosx)/(cosxsin^2*x) and (1-cosx)/(cosxsin^2*x) = (1-cosx)/cosx(1-cos^2*x) and (1-cosx)/cosx(1-cos^2*x) = 1/cosx(1+cosx) and 1/cosx(1+cosx) = 1/2
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