解方程组2X+YX^2=Y 2Y+ZY^2=Z 2Z+XZ^2=X

来源：学生作业帮编辑：搜搜考试网作业帮分类：数学作业时间：2024/04/29 16:10:54

这个题手算太困难了.我用MATLAB算出答案后发现实数解只有1组：
x=0,y=0,z=0
其余8组解全是虚数解,共9组解.
因为解析解太长,好几百位,故我给出数值
需要解析解的话百度HI我.这里给你一个x的虚数解析解给你看看.
x=
- (15*(7 - (224 + (224*27^(1/2)*i)/27)^(1/3)/2 - 56/(3*(224 + (224*27^(1/2)*i)/27)^(1/3)) + (3^(1/2)*(112/(3*(224 + (224*27^(1/2)*i)/27)^(1/3)) - ((224*27^(1/2)*i)/27 + 224)^(1/3))*i)/2)^(1/2))/4 + 5*(7 - (224 + (224*27^(1/2)*i)/27)^(1/3)/2 - 56/(3*(224 + (224*27^(1/2)*i)/27)^(1/3)) + (3^(1/2)*(112/(3*(224 + (224*27^(1/2)*i)/27)^(1/3)) - ((224*27^(1/2)*i)/27 + 224)^(1/3))*i)/2)^(3/2) - (7 - (224 + (224*27^(1/2)*i)/27)^(1/3)/2 - 56/(3*(224 + (224*27^(1/2)*i)/27)^(1/3)) + (3^(1/2)*(112/(3*(224 + (224*27^(1/2)*i)/27)^(1/3)) - ((224*27^(1/2)*i)/27 + 224)^(1/3))*i)/2)^(5/2)/4

解方程组2X+YX^2=Y 2Y+ZY^2=Z 2Z+XZ^2=X 解方程组xy+xz=8-x^2,yx+yz=12-y^2,zy+zx=-4-z^2 已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3 ∫∫∑(xz^2+1)dydz+(yx^2+2)dzdx+(zy^2+3)dxdy,其中,∑是锥面z=√x^2+y^2( 解三元一次方程组 x+y+z=26 x-y+xz=1 2x-y+z=18 若x/3=y/1=z/4,且xy+xz+zy=76,求2x(2)+12y(2)+9z(2) 三元二次方程组(XY+X)/(X+Y+1)=2(XZ+2X)/(X+Z+2)=3(Y+1)(Z+2)/(Z+Y+3)=4 已知2的X次方等于5的Y次方等于10的Z次方,求证：XY=XZ+YX 已知:xyz=1,x+y+z=2,x^2+y^2+z^2=16求1/(xy+2z)+1/(zy+2x)+1/(xz+2y 实数x、y、z满足x=6-3yx+3y-2xy+2z 解方程组:1、（x+2y-z）^2+(z-x)^2=0 2、xz^2+yz-5根号下(xz^2+yz+9)+3=0 解方程组（x+y)/xy=5/6,(y+z)/yz=-2/3,2(x+3)+xz=0