文科高数题目lim [ln(1+2x)]/tan4x x趋近于0 答案是1/2
文科高数题目lim [ln(1+2x)]/tan4x x趋近于0 答案是1/2
lim x趋近于0 (arctanx-x)/ln(1+2x^3)答案是多少?
x趋向于0+,lim(ln(tan4x)/ln(tanx))
lim(x趋近于0)[1/ln(x+根号1+x^2)-1/ln(1+x)]
文科高数题目lim[1/(x+1)-3/(x^3+1)] x趋向于-1 lim[(e^2x-1)/x] x趋向于0 没学
lim(tan4x)^2/2*(1-cosx^2)(x趋向于0)
lim(cos(1/x)+2/sinx-1/ln(1+x)) x趋近于0
lim ln (2+x^2)/ cos(1+x^2),x趋近于0
当x趋近于0时,lim [1-cos(sinx)]/ln(1+x^2)
【急】大一微积分lim[x-x^2ln(1+1/x)] x趋近于无穷
当x趋近于1时 lim[ln(2-x)tan(派/2*x)]
lim{[sinx+(x^2)*sin(1/x)]/[(1+cosx)ln(1+x)]}(x趋近于0)