a=b=c=(int*)malloc(sizeof(int))是什么意思?
a=b=c=(int*)malloc(sizeof(int))是什么意思?
mai() {int *a,*b,*c; a=b=c=(int*)malloc(sizeof(int)); *a=1;*
一道函数测试题!void func(int *x){ x=(int *)malloc(sizeof(int));*x=1
n = sizeof(a)/sizeof(int); 什么意思啊?
#include int func(int a,int b) { int c; c=a+b;return c; } ma
#include int max(int a,int b,int c){\x05a=a>b?a :b ;\x05retu
#include func(int a,int b) {int c; c=a+b; return c;} main()
Birds *Bird = (Birds*)malloc(sizeof(Birds));
W=(complex *)malloc(sizeof(complex) *
下列程序的输出结果是 int b=2; int func(int *a) { b += *a; return(b);}
#include func(int a,int b){int c; c=a+b;returnc;}main(){intX
func(int a,int b) {int c; c=a+b; return(c); } main() {int x=