1题 (lg根号2+lg3-lg根号10)/lg1.8
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1题 (lg根号2+lg3-lg根号10)/lg1.8
2题 已知以6为底7的对数=a,以3为底4的对数是b,求以12为底7的对数?
2题 已知以6为底7的对数=a,以3为底4的对数是b,求以12为底7的对数?
(lg根号2+lg3-lg根号10)/lg1.8
=lg(√2*√9/√10)/lg1.8
=lg√1.8/lg1.8
=(1/2)*lg1.8/lg1.8
=1/2
log6(7)=a
lg7/(lg2+lg3)=a
lg7=alg2+alg3
log3(4)=b
2lg2/lg3=b
lg2=(b/2)lg3
所以lg7=a(b/2)lg3+alg3=(a+ab/2)lg3
log12(7)
=lg7/(2lg2+lg3)
=(a+ab/2)lg3/[2*(b/2)lg3+lg3]
=(a+ab/2)/[2*(b/2)+1]
=(2a+ab)/(2b+2)
=lg(√2*√9/√10)/lg1.8
=lg√1.8/lg1.8
=(1/2)*lg1.8/lg1.8
=1/2
log6(7)=a
lg7/(lg2+lg3)=a
lg7=alg2+alg3
log3(4)=b
2lg2/lg3=b
lg2=(b/2)lg3
所以lg7=a(b/2)lg3+alg3=(a+ab/2)lg3
log12(7)
=lg7/(2lg2+lg3)
=(a+ab/2)lg3/[2*(b/2)lg3+lg3]
=(a+ab/2)/[2*(b/2)+1]
=(2a+ab)/(2b+2)
1题 (lg根号2+lg3-lg根号10)/lg1.8
【根号(lg3的平方-lg9+1)*(lg根号27+lg8-lg根号1000)】/(lg0.3)*(lg1.2)
(lg根号2的对数+lg3的对数—lg根号10的对数)除以lg1.8的对数 该如何运算?
根号下{(lg3)平方-lg9+1}乘以(lg根号下27+lg8-lg根号下1000)再整体除以lg0.3乘以lg1.2
(lg根号27+lg8-3lg根号10)/lg3+2lg2-1
计算:(lg根号8 + lg27 - lg根号1000)/lg1.8
(lg根号27+lg8-lg根号1000)/lg1、2
急(lg根号下27+lg8-lg根号下1000)\lg1.2=(3/2lg3+3lg2-3/2)/lg1.2然后呢
【根号(lg的平方3-lg9+1)*(lg根号27+lg8-lg根号1000)】/(lg0.3)*(lg1.2)
求(lg根号27+lg8-3lg根号10)/lg1.2
【lg(根号下27)+lg8-3(lg根号下10)】÷lg1.2=?
(lg根号27+lg8-3lg根号10)除以lg1.2