(2012•海门市一模)(1)计算:−12012+(12)−2−(tan62°+2π)0+|27−8sin60°|,
(2012•海门市一模)(1)计算:−12012+(12)−2−(tan62°+2π)0+|27−8sin60°|,
(2013•历城区二模)(1)计算:−22−12+|1−4sin60°|+(π−23)0;
(2014•响水县二模)(1)计算:(12)2-2sin60°+12; &
(2013•海门市一模)解方程:5x−4x−2−4x+103x−6=−1
(2010•天桥区二模)(1)计算:13+1+(3-π)0-sin60°
计算:2sin60°+/-3/-根号12-(3分之1)负一
(2011•江苏模拟)(1)计算:|1-3|-sin60°+(-25)0-124.
计算(-根号下2)的0次幂-(3分之1)的-1次幂-|-根号下3|+2sin60°
sin60°=根号3/2 如何计算出来
(2012•海门市一模)所示实验能达到目的是( )
(2012•海门市一模)下列实验操作中发生化学变化的是( )
计算:sin60°-cos60°+2sin30°cos30° 根号三sin60°-根号2cos45°+根号8的立方