数学题1/3-x-2=1/x-3+4-2x/3x^2-27

来源：学生作业帮编辑：搜搜考试网作业帮分类：数学作业时间：2024/04/30 18:00:34

1/(3-x) - 2 = 1/(x-3) + (4-2x)/(3x^2-27)
移项：1/(3-x) - 2 - 1/(x-3) - (4-2x)/(3x^2-27) = 0
- 1/(x-3) - 2 - 1/(x-3) - 2 (2-x)/{3（x+3)(x-3)} = 0
2/(x-3) + 2 + 2(2-x)/{3（x+3)(x-3)} = 0
1/(x-3) + 1 + (2-x)/{3（x+3)(x-3)} = 0
{3(x+3) + 3(x+3)(x-3) + (2-x) } / {3（x+3)(x-3)} = 0
{3x+9 + 3x^2-27 + 2-x } / {3（x+3)(x-3)} = 0
{ 3x^2+2x-16 } / {3（x+3)(x-3)} = 0
(3x+8)(x-2) / {3（x+3)(x-3)} = 0
(3x+8)(x-2) = 0
x1=-8/3,x2=2

数学题1/3-x-2=1/x-3+4-2x/3x^2-27 x^5+x^4 = (x^3-x)(x^2+x+1)+x^2+x 数学题（x-1)(x-3)(x+4) x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4 x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002 一道数学题：1/x-1+1/(x-1)(x-2)+1/(x-2)(x-3)+.+1/(x-99)(x-100) 初升高数学题分解因式X^4-4X^3+3X^2+2X+1 数学题因式分解[X加1]×[X加2]×[X加3]×[X加4]加1 初一数学题（x-1)(x-2)(x-3)(x-4)有没有简单方法计算? |X-1|+|X-2|+|X-3|+|X-4|+|X-5|+|X-6|+|X-7|+|X-8|+|X-9|+|X-10| 1/(x-4)(x-3)+1/(x-3)(x+2)+1/(x-2)(x-1)+1/(x-1)x+1/x(x+1)=1/x 已知1+x+x^2+x^3=0,求x+x^2+x^3+x^4+x^5+x^6+x^7+x^8的值