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杭电ACM MAX SUM题目看不懂

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杭电ACM MAX SUM题目看不懂
Max Sum
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 38673 Accepted Submission(s): 8367
Problem Description
Given a sequence a[1],a[2],a[3]......a[n], your job is to calculate the max sum of a sub-sequence. For example, given (6,-1,5,4,-7), the max sum in this sequence is 6 + (-1) + 5 + 4 = 14.
Input
The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line starts with a number N(1<=N<=100000), then N integers followed(all the integers are between -1000 and 1000).
Output
For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line contains three integers, the Max Sum in the sequence, the start position of the sub-sequence, the end position of the sub-sequence. If there are more than one result, output the first one. Output a blank line between two cases.
Sample Input
2
5 6 -1 5 4 -7
7 0 6 -1 1 -6 7 -5
Sample Output
Case 1:
14 1 4
Case 2:
7 1 6
就是那个举例怎么得到的搞不懂。跪求思路。好的话加分。(怕分被吞掉就不弄了)
杭电ACM MAX SUM题目看不懂
就是求子序列的和的最大值,子序列必须是连续的,这样举例中就很容易理解了,6,-1,5,4,-7
自然是-7不要,其它都算进去,把-1也算进去是为了把6加进去