5、int y=1, x, *p, a[ ]={2,4,6,8,10}； 　　p=&a[1]；

main(){int a[]={2,4,6,8,10};int y=1,x,*p;p=&a[1];for(x=0;x int a[3][3]={{1,2,3},{4,5,6},{7,8,9}}; int **p; p=(int**)a; main() {int a[]={2,4,6,8,10},y=0,x,*p; p=&a[1]; for(x=1;x struct st{int x,int*y;}*p; int s[]={5,6,7,8} st a[]={10,&s[0 { int a[]={1,2,3,4,5,6}; int*p; p=a; printf("%d\n",*p); prin int a[5]={2,4,6,8,10},*P,* *k; p=a; k=&p; printf("%d",*(p++) int a[]={1,2,3,4,5,6,7,8,9},*p; for(p=a,p int a[3][5]={{1,2},{6,4},{3,4,5}}； int (*p)[5] = a; 求*(*p+1) Int a=1; Int *p; p=&a; printf(“%d\n”,*p); 和Int a=1; Int*p; * 有如下程序,int a[10]={1,2,3,4,5,6,7,8,9,10}; int *p=&a[3],b;b=p[5 struct m { int x; int *y; }*p; int a[4]={12,13,-40,100}; main() {int a[5]={2,4,6,8,10},*p,**k; p=a; k=&p; printf("%d"