log(x²-10)-log(9x²)=-1 ,X怎麼求?
1/log(2)x+1/log(3)x+1/log(4)x=1,x=?
对数计算1.{log(4)(3)+ log(8) (3)} X {log(3)(2)+log(9)(2)}2.{log(
log(x+5)=log(x)+log(2) log(8)+log(x)=log(24) 2log(x)=log(2x)
已知log(2)[log(3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x
log底数7[log底数3(log底数2X)]=0,那么x^1/2的值是
log(0.1)log(0.2)log(0.5)(1/根号5次2)=x,求x的值
求下式x值log₂(1og₃(log底数5x))=0
请画出下列图像:log 1/2 (-x) y=log 1/3 /x/
(高一)若x满足2(log(1/2)x)^2-14log(4)x+3≤0,求f(x)=[log(2)(x/2)]*{lo
解不等式2(log½(x))²+9log½(x)+9≤0
log₂log₃log₄ X=log₃log₄logS
log底数9 [ log底数3(log底数2真数x)]=0,则x的-1/3方=