化简f(x)=cos^2(x+π/12)+sinxcosx
已知函数f(x)=1+sinxcosx,g(x)=[cos(x+(π/12))]^2
f(x)=2sin^2x+cos^2x+sinxcosx,x∈R,f(π/12)
已知函数f(x)=cos^2x+sinxcosx
已知函数f(x)=cos^2(x+π/12)+sinxcosx.求f(x)的最值.
已知函数f(x)=1+sinxcosx,g(x)=cos²(x+π/12)
已知f(x)=cos^4x-2根号3sinxcosx-sin^4x 化简
已知函数f(x)=2√3sinxcosx-2cos(x+π/4)cos(x-π/4) ,
已知函数f(x)=3sinxcosx-cos(2x+π3)-cos2x
已知f(x)=cos^2x+sinxcosx g(x)=2sin(x+π/4)sin(x-π/4)
f(x)=2根号3sinxcosx=2cos^2x+1 (1)求f(5/12 π) (2)求函数f(x)的对称轴方程
已知函数f(x)=cos^2x+sinxcosx(x∈R) 求f(π/8)的值
已知函数f(x)=cos^2x+sinxcosx,求f(x)的单调递增区间