已知(1+tanx)/(1-tanx)=3+2√2,求(sin^2x+√2sinx*cosx-cos^2x)/(sin2
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已知(1+tanx)/(1-tanx)=3+2√2,求(sin^2x+√2sinx*cosx-cos^2x)/(sin2x+cos^x)的
已知(1+tanx)/(1-tanx)=3+2√2,求(sin^2x+√2sinx*cosx-cos^2x)/(sin2x+cos^x)的值
已知(1+tanx)/(1-tanx)=3+2√2,求(sin^2x+√2sinx*cosx-cos^2x)/(sin2x+cos^x)的值
(1+tanx)/(1-tanx) =3+2√2 ,
解得tanx=√2/2.
(sin^2 x+√2sinx*cosx-cos^2 x)/(sin^2 x+2cos^2 x)
=(tan^2x+√2tanx-1)/(tan^2x+2)
=(1/2+1-1)/(1/2+2)
=1/5.
解得tanx=√2/2.
(sin^2 x+√2sinx*cosx-cos^2 x)/(sin^2 x+2cos^2 x)
=(tan^2x+√2tanx-1)/(tan^2x+2)
=(1/2+1-1)/(1/2+2)
=1/5.
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