高分急求x2+y2+z2+2x+2y+2z+14=0,求x+y+z=?
高分急求x2+y2+z2+2x+2y+2z+14=0,求x+y+z=?
1.已知x2+y2+z2-2x+4y-6z+14=0,求x+y+z的值.
已知x2+4y2+z2-2x+4y-6z+11=0 求x+y+z的值
x+y+z=4 xy+yz+xz=4求x2+y2+z2的解 已知x2+y2+z2-2x+4y-6z+14=0求x+y+z
已知2x+3y+4z=10,求x2+y2+z2的最小值.
已知x2+y2+z2≤2x+4y-6z-14,求x2+y2+z2的值.
已知x+y+z=1,x2+y2+z2=2,x3+y3+z3=3,求xy(x+y)+yz(y+z)+zx(z+x)的值
已知xyz=1,x+y+z=2,x2+y2+z2=16,求1/x+y+1/y+z+1/x+z
已知x+y+z=1,xy+yz+zx=2,xyz2,求x2(y+z)+y2(z+x)+z2(x+y)的值
已知x2+y2+z2-2x+4y-6z+14=0,则x+y+z=______.
已知x,y,z满足x/(y+z)+y/(z+x)+z/(x+y)=1,求代数式x2/(y+z)+y2/(x+z)+z2/
已知实数x,y,z满足x/(y+z)+y/(z+x)+z/(x+y)=1,求x2/(y+z)+y2/(z+x)+z2/(