for (y=1;y
for(y=1;y
for (y=1;y
matlab for i=1:length(y)
# include main (){ int y=10;for( ; y>0; y - -)if ("y%3" == 0
for(x=1,y=0;(y!=123)&&(x
for(int x=0,y=0;!x&&y
int y=9;for(;y>0;y--) if(y%3==0) printf("%d",--y);
int y=7; for(;y>0;y--) { if(y%3==0) continue; printf("%d",y)
以下for循环是( ).for(x=0,y=0;(y!=123) && (x
求x=?,y=?Int x=1,y=0;For(int k=0;k
Private Sub Form_Click() x = 1 y = 5 z = 2 For k = x To y St
解方程:3y^2-(2y+1)(y-1)=(y-5)(y+1)