∫sec^4x dx ∫sec^2x tan^2x dx

来源：学生作业帮编辑：搜搜考试网作业帮分类：数学作业时间：2024/05/13 02:30:38

sec^4x =sec^2x *(1/cos^2x )=sec^2x *tan^2x *(1/sin^2x )=sec^2x *tan^2x *csc^2x
所以原题∫sec^4x dx =∫sec^2x tan^2x *csc^2x dx

∫sec^4x dx ∫sec^2x tan^2x dx ∫ sec^2 x dx ∫(tan^(5)(x)*sec^(4)(x))dx ∫secx/sec^2x-1 dx ∫（sec^2x+sinx)dx ∫cosx cos3x dx ∫tan^3t sect dt ∫(sec^2x)/4+tan^2 dx 不定积分∫sec^4 x dx 求积分∫（sec^2x/2+tan^2x）dx ∫1/根号x*sec^2(1-根号x)dx ∫tan^2xdx=∫(sec^2x-1)dx 1、∫[2/(1+x^2) -sec^2)dx ∫1/(sec^2x+1)dx等于多少?