sin(x-1)的导数
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/13 09:48:14
[sin(x^5)]'=cos(x^5)×(x^5)'=cos(x^5)×5x^4=5x^4cos(x^5)
(x*cosx-sinx)/x^2
-3(sin(1/x))^2acos(1/x)/x^2再问:过程再答:=3(sin(1/x))^2(sin(1/x))'=3(sin(1/x))^2cos(1/x)(1/x)'=-3(sin(1/x)
(sinx)^2求导是2sinxcosxsin(x^2)求导是2xcos(x^2)
∫sin²xdx=∫(1-cos2x)/2dx=1/2·∫1dx-1/2·∫cos2xdx=x/2-1/4·sin2x+C所以x/2-1/4·sin2x+C的导数是sin²x
y'=[-sinx(1-sinx)-cosx(-cosx)/(1-sinx)²=[-sinx+sin²x+cos²x]/(1-sinx)²=1/(1-sinx)
f'(x)=lim(Δx-->0)Δy/Δx=lim(Δx-->0)[sin(3x+3Δx+1)-sin(3x+1)]/Δx=lim(Δx-->0)[2cos(3x+3/2*Δx+1)sin(3Δx/
5sin^4x*cosx
y=sin^3x是复合函数可以设t=sinxt'=cosxy=t^3y'=3t^2*t'y'=3sin^2x*cosx
∵y=x^(sinx)∴lny=sinx*lnx两边求导:y'/y=cosx*lnx+(sinx)/x∴y'=y[cosx*lnx+(sinx)/x]=x^(sinx)[cosx*lnx+(sinx)
f(x)=sin[2^x-2^(1/x)]f'(x)=cos[2^x-2^(1/x)]*[2^x-2^(1/x)]'=[2^x*ln2-2^(1/x)*ln2*(1/x)']*cos[2^x-2^(1
(sin(x/2))'=(1/2)cos(x/2).再问:帮我做下这个好吗?
f'(x)=lim(h→0)[f(x+h)-f(x)]/h=lim(h→0)[sin(e^(x+h)+1)-sin(e^x+1)]/h由和差化积公式得=lim(h→0)2cos[(e^(x+h)+e^
cosx谢谢o(︶︿︶)o再问:лл
[sin(1/x)]'=cos(1/x)(-1/x^2)=-1/x^2cos(1/x)
用链式法则:y=sin(πx)dy/dx=dsin(πx)/d(πx)*d(πx)/dx=cos(πx)*π(dx/dx)=cos(πx)*π=πcos(πx)
y=1+1/2*sinxy'=1/2*cosx
因为sin[2*(x/2)]=2sin(x/2)cos(x/2)所以x-sin(x/2)cos(x/2)=x-1/2sinx导数为1-1/2cosx
=[sin(1-x)]'=cos(1-x)*(1-x)'=-cos(1-x)
(x*sinx*cosx)'=(1/2xsin2x)'=1/2(sin2x+xcos2x*2)=1/2sin2x+xcos2x