搜搜考试网log3√2称log49 81
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/29 05:28:19
根据对数函数的性质log(a)(M^n)=nlog(a)(M),log(a)(MN)=log(a)(M)+log(a)(N);所以,log3(8)-2log3(6)=log3（2的3次方）-2×（lo
(log34+log38)(log23+log29)+(log3根号2)(log97)/[(log1/37)(log三次根号48)]=(5lg32)(3lg32)+[9(lg23)(lg37)/4]/
log₂3=a,==>log₃2=1/alog₃7=b用换底公式：log3√7^（2√21）=log₃(2√21)/log₃(3√7)=[l
log243÷log9=log3^5÷log3^2=5log3÷（2log3）=5/2=2.5
=(log(2,3)/2+log(2,3)/3)*(log(3,2)+1/3-?)log(a,b)=ln(b)/ln(a)
log35-log315+1/2log927=log35-log315+1/2(lg27/lg9)=log3(5÷15)+1/2(3lg3/2g3)=log3(1/3)+1/2*3/2=log33^(
等差2log3(2^x-1)=log3(2)+log3(2^x+11)log3(2^x-1)²=log3[2(2^x+11)]所以(2^x-1)²=2(2^x+11)令a=2^x>
点击图片就可以看清楚了,加油!
log2(3)+log3(5)+log3(2)=log2(3)+log3(10)=4.2429387700296再问：=1g3/1g2+(lg5+lg2)lg3这个式子最后那个lg3原来是分母，，怎么
log3八次方-2log3六次方=4log3²-2×3log3²=-2log3²=-2a
log31/64×log4√5×log1/2527=log32^(-6)×log2^25^(1/2)×log5^(-2)3^3=[(-6)×log32]×[(1/2)×(1/2)×log25]×[(-
=(lg2/lg3)*(lg9/lg8)(换底）=(lg2*lg9)/(lg3*lg8)=(lg2*2lg3)/(lg3*3lg2)=2/3
log38-2log36=a-log336=a-log34×9=a-2/3log38-log39=a-2a/3-2=a/3-2再问：log34乘以9=log34+log39吗再答：对
=log3(4√27）-log3(3)+lg25*4+7=1/4log3(27)-1+lg100+7=1/4log3(3的3次方）-1+lg(10的2次方）+7=（1/4）3log3(3)-1+2lg
(1).2log₃2-log₃(32/9)+log₃8=2log₃2-(5log₃2-2)+3log₃2=2(2).(9/4)^
如果你的问题是：log3(x^2+2)=（log3x）+1则是下面答案：先建立方程：x^2+2=3x（X>0）解答上面方程x^2-3x+2=0得到结果：x=1或x=2
[(9^2*27^(1/3))/3^(log3234)]=(9^2*27^(1/3))/3^(log3234)=(81*3)/(234)=3^5/234log3[(9^2*27^(1/3))/3^(l
log3(27/5)+log3(2/3)-log3(6/5)=log3(27/5×2/3÷6/5)=log3(3)=1
（2+log3x)log3x>log3(9x)=>（2+log3x)log3x>log3(9)+log3(x)=>（2+log3x)log3x>2+log3(x)设log3(x)=t=>(2+t)t>