5倍的(log以5为底的3)次方等于
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/06 13:26:08
log2(25)*log3(1/16)*log5(1/9)=[2log2(5)]*[-4log3(2)]*[-2log5(3)=[2*lg5/lg2]*[-4*lg2/lg3]*[-2*lg3/lg5
(log5√2×log4981)÷(log251/3×log74∧3)=[1/2lg2×4lg3/(lg5×2lg7)]/[-lg3×6lg2/(2lg5×lg7)]=(lg2×lg3/lg5×lg7
为了书写方便,不妨记以a为底b的对数为:log【a】b(log【2】5+log【4】125)×[(log【3】2)/(log【√3】5)]=[(lg5)/(lg2)+(lg125)/(lg4)]×{[
2log(3)2-log(3)32/9+log(3)8-5^log(5)3=2log(3)2-log(3)2^5+log(3)9+log(3)2^3-3=2log(3)2-5log(3)2+log(3
6手机难打对数,用换底功式,等我回家用电脑打给你过程?
log以3为底2的对数log以2为底3的对数>log以2为底2的对数=1>log以3为底2的对数
=log(9开立方)=log2.08=0.3181
9乘以log以3为底5的对数=9×[(log5)÷(log3)]=9×[0.69897000433601880478626110527551÷0.477121254719662437295027903
log2(25)*log3(4)*log5(9)=lg25/lg2*lg4/lg3*lg9/lg5(换底公式)=lg5^2/lg2*lg2^2/lg3*lg3^2/lg5=2lg5/lg2*2lg2/
8再问:是不是换成分数形式可以互相约掉再答:log2(25)*log3(4)*log5(9)=lg25*lg4*lg9/lg2*lg3*lg4=log2(4)*log3(9)*log5(25)=2*2
log2(25)*log3(4)*log5(9)=lg25/lg2*lg4/lg3*lg9/lg5(换底公式)=lg5^2/lg2*lg2^2/lg3*lg3^2/lg5=2lg5/lg2*2lg2/
(lg3/lg5)[(3lg5)/(3lg3)]=1
不等于.再看看题.有没有看错再问:谢谢你哦,那可是等于log以3为底的4分之3为真数
log以2为底25乘以log以3为底2√2乘以log以5为底9=2log25×(3/2)log32×2log53=6log25×log32×(log23/log25)=6(log25×1/log52)
log(5^2/3)5=lg5/lg(5^2/3)=lg5/[2/3lg5]=3/2
2log3(2)-log3(32/9)+log3(8)-5*2*log5(3)=log3(4)-log3(32/9)+log3(8)-5*2*log5(3)=log3(4/(32/9))+log3(8
log_3[log_4(log_5(a))]=0(1)log_4[log_3(log_5(b))]=0(2)(1)=>log_4(log_5(a))=1=>log_5(a)=4=>a=5^4(2)=>