{y-1/2x+1=0 {2y+3(x-2/2)-10=10 {11x+3z=9 {3x+2y+z=8 {2x-6y+4
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{y-1/2x+1=0 {2y+3(x-2/2)-10=10 {11x+3z=9 {3x+2y+z=8 {2x-6y+4z=5
二元一次方程 和 三元
{y-1/2x+1=0 {2y+3(x-2/2)-10=10
{11x+3z=9 {3x+2y+z=8 {2x-6y+4z=5
二元一次方程 和 三元
{y-1/2x+1=0 {2y+3(x-2/2)-10=10
{11x+3z=9 {3x+2y+z=8 {2x-6y+4z=5
你这个是分两题的吗.
∵y-1/2x+1=0 ∴y=1且x≠-1/2
∵ 2y+3(x-2/2)-10=10 ∴x=14
同理下一题利用11x+3z=9将z用x带掉,即z=(9-11x)/3
再带入{3x+2y+z=8 {2x-6y+4z=5将他们看成二元一次方程 进行计算
∵y-1/2x+1=0 ∴y=1且x≠-1/2
∵ 2y+3(x-2/2)-10=10 ∴x=14
同理下一题利用11x+3z=9将z用x带掉,即z=(9-11x)/3
再带入{3x+2y+z=8 {2x-6y+4z=5将他们看成二元一次方程 进行计算
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
(x-2y+z)/9=(2x+y+3z)/10=-(3x+2y-4z)/3=1 连等,求x,y,z,
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2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X
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如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
解三元一次方程组:(1)x+2y+3z=11x-y+4z=10x+3y+2z=2(2)x:y=3:5y:z=5:6x+y
若4x-3y-6z=0,x+2y-7z=0,求代数式5x*5x+2y*2y-z*z/2x*2x-3y*3y-10z*10
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①x+y+z=6 3x-y+2z=12 x-y-3z=-4 ②x+y-z=2 4x-2y+3y+8=0 x+3y-2z-
解方程:(1)4x+7y=10 (2)x+y-z=0 6x-11y+28=0 x+2y-z=3 2x-3y+2z=5