log2^1/25×log3^8÷log9^5+(-1/2)^-2×(In兀)^0÷8^2/3
(log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)
(log2(3)+log8(9))x(log3(4)+log9(8)+log3(2))
(log2 3+log8 9)(log3 4+log9 8+log3 2)的运算过程
1.log2 3*log3 4*log4 5*log5 2 2.(log4 3+log8 3)8(log3 2+log9
(log2^3 +log3^5) x ( log3^5 +log9^5 ) x lg 2 ,
计算(log4 3+ log8 3)(log3 2+ log9 2)-- log1/2 32^(1/3)+5^(log2
[log2(3)+log4(9)][log3(4)+log9(2)]等于
log3 5-log3 15+1/2log9 27 的值
(log4^3+log8^3)(log3^2+log9^2)+log2^(32)的1/4次方
(1)log4 27乘以log25 8乘以log9 5 (2)(log4 3+log8 3)(log3 2+log9 2
[log4(3)/log4(8)][log3(2)log9(2)]
log 243÷log9 =log3^5÷log3^2 =log3^5-log3^2 然后怎么写