数列an满足an+1=2an (0≤an<1/2) 2an-1 (1/2≤an<1) 若a1=6/7 则a2010的值为
已知数列an满足a1=0,an+1=an+2n那么a2010的值是
数列{an}满足a1=2,an+1=−1an+1,则a2010等于( )
已知数列{an}满足a1=2,an+1=1+an1−an(n∈N*),则a1a2a3…a2010的值为( )
若数列{An}满足An+1=An^2,则称数列{An}为“平方递推数列”,已知数列{an}中,a1=9,点(an,an+
已知数列{an}满足a1=1,an+1=2an+1 1)求证:数列{an+1}为等比数列; 2) 求{an}的通项an
一直数列{an}满足a1=0,an=(an-1 +4)/(2an-1) ,求 an
数列{an}满足a1=3/2,an+1=an2-an+1,则m=1/a1+1/a2+……+1/a2010的整数部分为
数列{an}中,a1=-2,an+1=1+an1−an,则a2010=( )
在数列{an}中,a1=1,a2=4,an+2=an+1-an,则a2010
已知数列{an}满足a1=1,an+1=2an/(an+2)(n∈N+),则数列{an}的通项公式为
数列{an}满足a1=3/2,an+1=an^2-an+1,则1/a1+1/a2+...+1/a2010+1/a2011
已知数列an满足a1=0 an+1=an-根号3/根号3an+1 则a2010的值为