lim(n->∞)[√(1+cosπ/n)+√(1+cos2π/n)+……+√(1+cosnπ/n)]*1/n=
求极限lim(x→无穷)1/n{(1+cosπ/n)^(1/2)+.+(1+cosn*π/n)^(1/2)} ..
计算极限lim(n→∞){1+ sin[π√(2+4*n^2)]}^n
求极限 lim (cosnπ/2)/n
求极限 lim n[1/(n^2+1)+1/(n^2+2^2)+……+1/(n^n+n^n)] (n趋向于无穷大,n^n
lim√n(√n+1-√n)(n趋近于无穷大)的极限
紧急:求 lim n*sin(π(n^2+2)^0.5)*(-1)^n,n趋向无穷大;
lim n*[(1– ln(n)/n)^n]极限
lim(n->无限)(√ n)sinn/(n+1)
lim(n->∞) n的1/n次方
请问如何证明lim(n→∞)[n/(n2+n)+n/(n2+2n)+…+n/(n2+nn)]=1,
利用欧拉公式证明cosθ+cos2θ+cos3θ+···+cosnθ=-1/2+sin(n+1/2)θ/sin(θ/2)
求极限:lim(x→0)[cosx+cos^x+cos3(次方)x+……+cosn(次方)x] /(cosx-1),[n