搜搜考试网①x^n+1*x^n-1 ②[(x+1/2y)^2+(x-1/2y)^2](2x^2-1/2y^2) ③（a-b)^2n
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①x^n+1*x^n-1 ②[(x+1/2y)^2+(x-1/2y)^2](2x^2-1/2y^2) ③（a-b)^2n+2+(a-b)^2n 因式分解
 ③（a-b)^2n](/uploads/image/z/20191247-71-7.jpg?t=%E2%91%A0x%5En%2B1%2Ax%5En-1+%E2%91%A1%5B%28x%2B1%2F2y%29%5E2%2B%28x-1%2F2y%29%5E2%5D%282x%5E2-1%2F2y%5E2%29+%E2%91%A2%EF%BC%88a-b%29%5E2n)
x²-2xy+y²-2x+2y+1
=(x-y)²-2(x-y)+1
=(x-y-1)²
-x^(n+1)+2x^n-x^(n-1)
=-x^(n-1)*x^2+2x^(n-1)*x-x^(n-1)
=-x^(n-1)[x^2-2x+1]
=-x^(n-1)(x-1)^2
1998×2000-1999²
=(1999-1)(1999+1)-1999²
=1999²-1-1999²
=-1
[ 三分之一(x+1)的四次方]的三次方×[-3（x+1）²]三次方
=[1/3*(x+1)^4]^3×[-3（x+1）²]^3
=1/27*(x+1)^12×[-27（x+1）^6
=-1*(x+1)^18
=-(x+1)^18
=(x-y)²-2(x-y)+1
=(x-y-1)²
-x^(n+1)+2x^n-x^(n-1)
=-x^(n-1)*x^2+2x^(n-1)*x-x^(n-1)
=-x^(n-1)[x^2-2x+1]
=-x^(n-1)(x-1)^2
1998×2000-1999²
=(1999-1)(1999+1)-1999²
=1999²-1-1999²
=-1
[ 三分之一(x+1)的四次方]的三次方×[-3（x+1）²]三次方
=[1/3*(x+1)^4]^3×[-3（x+1）²]^3
=1/27*(x+1)^12×[-27（x+1）^6
=-1*(x+1)^18
=-(x+1)^18
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