x²-4y²+(x-2y) =(x+2y)(x-2y)+(x+2y) 接下来还怎么算?
(2x-y)²-4(x-y)(x+2y)
化简:(2x-y)²-4(x-y)(x+y)
已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y
(x-2y)²+(2x-4y)(x+y)+(x+y)²
1、x(x-y)(x+y)-x(x+y)^2
[(y-2x)(-2x-y)-4(x-2y)²]*2y,其中x=1,y=2
x^2-y^2/x+y-4x(x-y)+y^2/2x-y,
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013
已知x²+y²+5=2x+4y,求代数式(2x²-(x+y)(x-y))x((x+y-1)
求因式分解(x-y)²-2(x-y)³和(x+y)(x-y)-x(x-y)