tan(-20/3π)
tan=3,π
求值tan(π/6-θ)+tan(π/6+θ)+√3tan(π/6-θ)tan(π/6+θ)
求解tan(20度)+tan(40度)+(根号3)tan(20度)tan(40度)的值是_______.
化简:[sin(π+α)*cos(π-α)*tan(π-α)]/[cos(π/2+α)*tan(3π/2-α)*tan(
tan(a-3/π) =2 tan(3/π-B)=2/5 求tan(a+b)=
已知tan a=3,求tan(a+π/4),tan(a-π/4)的值?
tan(a+b)=3/4,tan(a-π/4)=1/2,那么tan(b+π/4)等于多少
数学tan(α-π/2)=1/2 tan(π+β)=3 则 tan(α+β)=?
tanπ/3为什么等于根号3?
已知tanα=根号3 ,π
已知tanα=√3 π
若方程tan(2x+π3