已知y-x=3xy 求2x+5xy-2y/x-2xy-y

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已知y-x=3xy 求2x+5xy-2y/x-2xy-y
已知分式x(x-3)/(x^2+1)的值为零,则2x/(x^2-1)÷3x/(1-x)的值为多少,

∵x^2+1≠0,所以X（X-3）=0
∴X=0或3
化简第二个式子：原式=-2/3x+3
当x=0时,原式=-2/3
当x=3时,原式=-1/6
再问：那么第一个问题呢？
再答：更简单了
由y-x=3xy,得x-y=-3xy
∴原式=2（x-y）+5xy/x-y-2xy
=-xy/-5xy
=5

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