10y-2(7y-2)=5(4y+5)
10y+2(7y-2)=5(4y+3)+3y怎么算
(2y-3)(-y+4)=(y-2)(y-5)-3y(y-7/3)解方程
(-y+5+4y^2)-(-y^2+5y-4),其中y=-2
代数式4y² - 2y + 5 = 7,那么代数式2y² - y + 1
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
解方程:10y-2(7y-2)=5(4y+3)-2y怎么解
解方程:1/5(3-2y)=2-4-7y/10+y-2/2
[-(x-y)^2/xy]^-4*(y^2-xy/x)^3*(x^4/y^10)÷(xy-y^2/x)^-5=-y(y-
2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X
{2x+y/3-2y=0 2(2x+y)-5=7y
解3y+5/3y-6=1/2+5y-4/2y-4
解方程组(x+y)(x-2y)=-5 (x-y)(x+2y)=7