7+x2=6x怎么算?
方程7 / x2+x+ 3/ x2-x=6 / x2-x怎么解?
解方程:1/x2+x +1/x2+3x+2 +1/x2+5x+6 +1/x2+7x+12 +1/x2+9x+20=5/x
解方程 2/(x2-x)+6/(1-x2)=7/(x2+x)
解方程7/(x+x2)-3/(x-x2)=6/(x2-1)
1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=1/(x+4)
用换元法解(2(x2+1)/x)+(6x/x2+1)=7其中(x2+1/x)=y
已知x2+x-6=0,求代数式x2(x+1)-x(x2-1)-7的值.
1/(x2+x)+1/(x2+3x+2)+1/(x2+5x+6)+1/(x2+7x+12)=4/21
用换元法解方程2(x2+1)/x + 6x/(x2+1) =7
解分式方程2(x2+1)/x+1+6(x+1)/x2+1=7
因式分解:(x2-7x+6)(x2-x-6)+56
因式分解(x2+x+2)(x2+x+7)-6