已知x+y-z=-1,x²+y²-z²=-11,那么﹙2x-y²+2y﹚-﹙x&
已知方程组﹛x+4y-3z=0 4x-5y+2z=0 ,xyz≠0,求﹙3x²+2xy+z²﹚÷﹙x
若2x+5y+4z=6,3x+y-7z=-4,那么x+y-z的值是多少?
解方程组:2x-y+z=6.-3x+2y-z=-9.x+y-2z=-1求解
已知2x+y+z=26,x-y+z=18,求当x-y=1时,x*y*z等于多少?
已知x,y,z满足x+y+2z=1,x²+y²+6z+1.5=0,求x,y,z的值
25(x-y)²-10(y-z)+1因式分解
解方程组2x-y+3z=3,3x+y-2z=﹣1,x+y+z=5,若先消去Z得到含Y,X的二元一次方程组是什么
x/2=y/3=z/4则2x+y-z/3x一2y+Z
已知方程组{2x-y+z=3,3x+4y-z=8,x+y-2z=-3,
已知x+y+z=36,2x-y+z=18,则当x-y=1时,z=
已知x/2=y/3=z/5,且3x+4z-2y=40,求x、y、z的值﹔详解
已知有理数想x,y,z满足(x-4)²+3丨x+y-z丨=0,则,(5x+3y-3z﹚的2008次方的末尾数字