2/x²+x+3/x²-x-4/x²-1=0
已知f(x)={x²-3x+4(x>0),{1-x(x
(x+1-1/1-x)÷(x-x²/x-1) (x-4/x-x-6+ x+2/x-3)÷x+1/x-3
解方程:x(6-x)-2x(x+1)-(x^3-3x^4)/x²=4
x²+3x-2=0,x²-6x-6=0,3x²-4x-1=0,3x²+10x+3
(x-2)²=(2x-3)² x²-4x=0 3x(x+1)=3x+3 x²-2
3x²-(x-2)=0 (2x-1)(x+3)=4 x²-3x-4=0 x²-3x+18=
2x(x-1)=0 x²+4=4x (x-3)(x+1)=0 x²-3x+1=0
(X-1)(X-2)=70,(3-X)²+2X(X-1)=0,-3X²-4X+4=0,(3-X)
4x²-{-3x²-[5x-x²-(2x²-x)]+4x},其中x=½
x²+3x-1=0,1/(x-2)×(x²-4x+4)/(x+1)-(x-1)/(x+2)
已知1+X+X²+X³+X^4=0求多项式1+x+x^2+x^3+……+x^2009的值
(x+1)/(x²+3x+2)+(x²-2x)/(x²-4)