10x+16(10-x)=36
设f(x)=min{2∧x,x+2,10-x}(x≥0),求f(x)最大值
数学题(x-4)/(x-3)+(x-6)/(x-5)=(x-8)/(x-7)+(x-10)/(x-9)解方程,
(4X-10)+(X+10)=X+4X 方程怎么解?
4x-2=3x+1 -x+3=10 x-7=11-x x=四分之一x+6
解方程:1.60%+25=40 2.X-10%X=18 3.x+30%X=52 4.(1-25%)X=36
已知5x²-x的四次方-4=10(x²+x-2),求x的值
2X+4(X-12)=60 4X-2(50-X)=20 2X+5X+10(50-2X)=240 完整些)
解下列方程(2)4x²+12x+9=81 (4)2x²+3x=3 (6)x(2x-5)=4x-10
x*x+2x+x*x+10x+x*x+25+2x+x*x+1+1+16+x*x+4x*x+9-12x+16x*x+4-1
(x+10)+(X+8)+X\3=36
4(x-3)=2x 8x+0.5=4x+4.5 4x+20=6x-10 解方程
5.4x+x=12.8、x-0.36x=16这两道题怎么解?